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B) Herbert Hoover - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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g'(x) = 3x^2 - 4
Setting \( g'(x) = 0 \):
3x^2 - 4 = 0 \implies x^2 = \frac{4}{3} \implies x = \pm \frac{2}{\sqr...
Evaluate \( g(x) \) at these critical points:
At \( x = \frac{2}{\sqrt{3}} \):
g\left(\frac{2}{\sqrt{3}}\right) = \left(\frac{8}{3\sqrt{3}}\right) -...
This is negative, and at \( x = -\frac{2}{\sqrt{3}} \), it's positive....
Alternatively, use cubic formula or numerical solvers:
Using approximation or a calculator, the real roots are approximately:
One root near \( x \approx 0.542 \)

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