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Home » Breaking: Knicks Game Live on This Channel – Catch Every Shot, Lock It Now! - Abu Waleed Tea

Breaking: Knicks Game Live on This Channel – Catch Every Shot, Lock It Now! - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 Let the quadratic be \( f(x) = ax^2 + bx + c \).

📌 Using the points:

📌 For (1,4): \( a + b + c = 4 \)

📌 For (2,3): \( 4a + 2b + c = 3 \)

📌 For (4,15): \( 16a + 4b + c = 15 \)

📌 Subtract first from second: \( (4a + 2b + c) - (a + b + c) = 3 - 4 \Rightarrow 3a + b = -1 \) (eq1)

📌 Subtract second from third: \( (16a + 4b + c) - (4a + 2b + c) = 15 - 3 \Rightarrow 12a + 2b = 12 \Rightarrow 6a + b = 6 \) (eq2)

📌 Now subtract eq1 from eq2: \( (6a + b) - (3a + b) = 6 - (-1) \Rightarrow 3a = 7 \Rightarrow a = \frac{7}{3} \)

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Question: What is the sum of all of the positive odd divisors of $ 180...
Solution: First, factor $ 180 = 2^2 \cdot 3^2 \cdot 5 $. To find only...
The odd divisors of 180 are the divisors of $ 3^2 \cdot 5 = 45 $.
List all positive divisors of 45: $ 1, 3, 5, 9, 15, 45 $.
Now compute their sum:
+ 3 + 5 + 9 + 15 + 45 = 78
Thus, the sum of all positive odd divisors of 180 is $ \boxed{78} $.
Question: What is the remainder when $ 11071 + 11073 + 11075 + 11077 $...
Solution: We compute the sum modulo 8. First, reduce each term modulo...
\equiv 7 \pmod{8}, \quad 11073 \equiv 1 \pmod{8}, \quad 11075 \equiv 3...

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