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Home » Can we place 4 non-adjacent H’s in 7 positions? - Abu Waleed Tea

Can we place 4 non-adjacent H’s in 7 positions? - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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D(x) = x^2 + \frac{9}{16}x^2 + 3x + 4 = \frac{25}{16}x^2 + 3x + 4
D'(x) = \frac{50}{16}x + 3 = \frac{25}{8}x + 3 = 0 \Rightarrow x = -\f...
Substitute into the line equation to find $ y $:
y = \frac{3}{4} \cdot \left( -\frac{24}{25} \right) + 2 = -\frac{18}{2...
Thus, the closest point is $ \left( -\frac{24}{25}, \frac{32}{25} \rig...
\boxed{\left( -\frac{24}{25}, \frac{32}{25} \right)}
Question: A cloud computing consultant models data flow efficiency as...
Solution: First, expand $ (\sin x + \cos x)^2 = \sin^2 x + 2\sin x \co...
Let $ s = \sin x \cos x $. Then:
f(x) = 1 + 2s + \frac{1}{s}

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