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Home » \cdot 6^3 + 4 \cdot 6^2 + 3 \cdot 6^1 + 2 \cdot 6^0 - Abu Waleed Tea

\cdot 6^3 + 4 \cdot 6^2 + 3 \cdot 6^1 + 2 \cdot 6^0 - Abu Waleed Tea

📅 February 28, 2026 👤 scraface

Feb 28, 2026

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15a = 5
a = \frac{5}{15} = \frac{1}{3}
Substitute \( a = \frac{1}{3} \) back into Equation 1:
5\left(\frac{1}{3}\right) + b = 3
\frac{5}{3} + b = 3
b = 3 - \frac{5}{3} = \frac{9}{3} - \frac{5}{3} = \frac{4}{3}
Thus, the values of \( a \) and \( b \) are:
\boxed{a = \frac{1}{3}, \ b = \frac{4}{3}}
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