ight)^2 $ term has same denominator $ rac649 $, and $ y^2 $ has $ rac1929 $, so it's **elliptical** in $ x/z $-plane. But more precisely, since the equation resembles $ racx^2 + y^2a^2 + rac(z - z_0)^2b^2 = 1 $, with $ a - Abu Waleed Tea
Mar 01, 2026
Content is being prepared. Please check back later.