Let \(\mathbfv = eginpmatrix x \ y \ z \endpmatrix\), \(\mathbfa = eginpmatrix 1 \ 2 \ 3 \endpmatrix\), and \(\mathbfv imes \mathbfa = eginpmatrix 0 \ 0 \ 5 \endpmatrix\). - Abu Waleed Tea
Mar 01, 2026
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