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Home » Puisque \( 8 = 2^3 \), nous avons : - Abu Waleed Tea

Puisque \( 8 = 2^3 \), nous avons : - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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🔥 Popular Posts

A company offers a 15% discount on a product originally priced at $200...
Discount amount is \( 0.15 \times 200 = 30 \) dollars.
Discounted price is \( 200 - 30 = 170 \) dollars.
Tax amount is \( 0.08 \times 170 = 13.6 \) dollars.
Final price is \( 170 + 13.6 = 183.6 \) dollars.
A quadratic equation \( ax^2 + bx + c = 0 \) has roots 3 and 5. If \(...
Sum of roots is \( 3 + 5 = 8 \), so \( -\frac{b}{a} = 8 \).
\( b = -8a = -8 \times 2 = -16 \).
Product of roots is \( 3 \times 5 = 15 \), so \( \frac{c}{a} = 15 \).
\( c = 15a = 15 \times 2 = 30 \).

📝 Recent Posts

ho = 3c \sin(\phi)\) into \(z =
z = 3c \sin(\phi) \cos(\phi) = rac{3c}{2} \sin(2\phi).
Now express \(
ho^2 = x^2 + y^2 + z^2\):
But \(\sin^2\phi = 1 - \cos^2\phi = 1 - \left(rac{z}{
ight)^2 = 1 - rac{z^2}{x^2 + y^2 + z^2}\). So:
9c^2 \left(1 - rac{z^2}{x^2 + y^2 + z^2}
ight) = x^2 + y^2 + z^2.
Multiply through:
9c^2 - rac{9c^2 z^2}{x^2 + y^2 + z^2} = x^2 + y^2 + z^2.

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