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Home » scenic: $ rac26 = rac13 $ - Abu Waleed Tea

scenic: $ rac26 = rac13 $ - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 Thus, all vectors \(egin{bmatrix} a \ -rac{4a + 5}{3} \end{bmatrix}\) satisfy the condition.

📌 To write a specific solution, choose \(a = -1\):

📌 b = -rac{4(-1) + 5}{3} = -rac{-4 + 5}{3} = -rac{1}{3}

📌 So one such vector is:

📌 \mathbf{v} = egin{bmatrix} -1 \ -rac{1}{3} \end{bmatrix}

📌 However, since the problem asks for *a* vector, the general solution is parameterized. But for a concrete boxed answer, we present one valid example:

📌 oxed{egin{bmatrix} -1 \ -rac{1}{3} \end{bmatrix}}

📌 For a positive constant \(c\), a bioinformatician models cyclic gene expression using spherical coordinates. In spherical coordinates \((

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