Solution: The sine of $ \theta $ equals $ \frac\sqrt32 $ at $ 60^\circ $ and $ 120^\circ $ in the interval $ [0^\circ, 360^\circ] $. These angles correspond to the reference angle $ 60^\circ $ in the first and second quadrants. Thus, the solutions are $ \boxed60^\circ $ and $ \boxed120^\circ $. - Abu Waleed Tea