Solution: There are 11 integers (0–10), of which 6 are even (0, 2, 4, 6, 8, 10). The number of ways to choose 4 distinct even integers is $inom64$. The total number of ways to choose 4 distinct integers is $inom114$. The probability is $racinom64inom114 = rac15330 = rac122$. $oxed\dfrac122$ - Abu Waleed Tea