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Home » There are 4 such sets, so total for single violations: $ 4 \cdot 35 = 140 $ - Abu Waleed Tea

There are 4 such sets, so total for single violations: $ 4 \cdot 35 = 140 $ - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Let $ a = x $, $ b = 2y - z $. Then:
Now expand $ (2y - z)^2 $:
x^2 - (4y^2 - 4yz + z^2) = x^2 - 4y^2 + 4yz - z^2
Thus, the simplified expansion is $ oxed{x^2 - 4y^2 + 4yz - z^2} $.
Question: Factor the expression $ 9x^2 - 30xy + 25y^2 - 16z^2 $ comple...
First, group the first three terms:
Note that $ 9x^2 - 30xy + 25y^2 = (3x - 5y)^2 $, a perfect square.
This is a difference of squares: $ a^2 - b^2 = (a - b)(a + b) $, with...
The fully factored form is $ oxed{(3x - 5y - 4z)(3x - 5y + 4z)} $.Que...
Solution: Let $ v = \sqrt{u} $, so $ u = v^2 $. Substituting into the...

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