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Home » x = 2 \pm 2\sqrt3 - Abu Waleed Tea

x = 2 \pm 2\sqrt3 - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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x(x - 2)(x - 3) = 0.
So the solutions for $ x $ are $ x = 0, 2, 3 $. Since $ x = \sqrt{u} $...
u = 0^2 = 0, \quad u = 2^2 = 4, \quad u = 3^2 = 9.
The roots of the original equation are $ u = 0, 4, 9 $. Their sum is:
+ 4 + 9 = 13.
Thus, the sum of the roots is
\boxed{13}.
Question: Let $ f(x) $ be a polynomial such that
f(x^2 + 2) = x^4 + 4x^2 + 2.
Find $ f(x^2 - 2) $.

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