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Home » x = 5 : 125 + 100 = 225 - 192 = 33 â trop haut - Abu Waleed Tea

x = 5 : 125 + 100 = 225 - 192 = 33 â trop haut - Abu Waleed Tea

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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So \( a = 5b + 1 \), then \( N = 4(5b + 1) + 3 = 20b + 7 \)
Thus, \( N \equiv 7 \pmod{20} \)
Step 2: Incorporate \( N \equiv 4 \pmod{7} \)
Let \( N = 20b + 7 \). Then:
20b + 7 \equiv 4 \pmod{7} \Rightarrow 20b \equiv -3 \equiv 4 \pmod{7}
Since \( 20 \equiv 6 \equiv -1 \pmod{7} \), we have:
b \equiv 4 \pmod{7} \Rightarrow b \equiv -4 \equiv 3 \pmod{7}
So \( b = 7c + 3 \), then:
N = 20(7c + 3) + 7 = 140c + 60 + 7 = 140c + 67
Smallest positive \( N \) when \( c = 0 \): \( N = 67 \)

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